碰到这样的错误：JSONValue failed. Error is: Unescaped control character [0x09] //ps:用SBJson才会有这个提示，系统方法不会提示错误

有如下解决方案：

//去除未转义的控制字符

-(NSString *)removeUnescapedCharacter:(NSString *)inputStr

{

NSCharacterSet *controlChars = [NSCharacterSet controlCharacterSet];

NSRange range = [inputStr rangeOfCharacterFromSet:controlChars];

  if (range.location != NSNotFound) 

  {

      NSMutableString *mutable = [NSMutableString stringWithString:inputStr];

      while (range.location != NSNotFound) 

      {

          [mutable deleteCharactersInRange:range];

          range = [mutable rangeOfCharacterFromSet:controlChars];

      }

      return mutable;

   }

  return inputStr;

}

//你可以这样调用 Call this method with passing your output string like this

NSString *output = [NSString stringWithContentsOfURL:[NSURL URLWithString:@"yourUrlString"] encoding:NSUTF8StringEncoding error:nil];

output = [self removeUnescapedCharacter:output];